tsk->exit_state can only be 0, EXIT_ZOMBIE, or EXIT_DEAD.  A non-zero test
is the same as tsk->exit_state & (EXIT_ZOMBIE | EXIT_DEAD), so just testing
tsk->exit_state is sufficient.
Signed-off-by: Eugene Teo <eugeneteo@kernel.sg>
Cc: Roland McGrath <roland@redhat.com>
Cc: Oleg Nesterov <oleg@tv-sign.ru>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
                                            TASK_UNINTERRUPTIBLE |
                                            TASK_STOPPED |
                                            TASK_TRACED)) |
-                       (tsk->exit_state & (EXIT_ZOMBIE |
-                                           EXIT_DEAD));
+                                          tsk->exit_state;
        const char **p = &task_state_array[0];
 
        while (state) {
 
 
 void __put_task_struct(struct task_struct *tsk)
 {
-       WARN_ON(!(tsk->exit_state & (EXIT_DEAD | EXIT_ZOMBIE)));
+       WARN_ON(!tsk->exit_state);
        WARN_ON(atomic_read(&tsk->usage));
        WARN_ON(tsk == current);
 
 
        struct rq *rq = cpu_rq(dead_cpu);
 
        /* Must be exiting, otherwise would be on tasklist. */
-       BUG_ON(p->exit_state != EXIT_ZOMBIE && p->exit_state != EXIT_DEAD);
+       BUG_ON(!p->exit_state);
 
        /* Cannot have done final schedule yet: would have vanished. */
        BUG_ON(p->state == TASK_DEAD);