+/*
+ * Calculate the preemption granularity needed to schedule every
+ * runnable task once per sysctl_sched_latency amount of time.
+ * (down to a sensible low limit on granularity)
+ *
+ * For example, if there are 2 tasks running and latency is 10 msecs,
+ * we switch tasks every 5 msecs. If we have 3 tasks running, we have
+ * to switch tasks every 3.33 msecs to get a 10 msecs observed latency
+ * for each task. We do finer and finer scheduling up to until we
+ * reach the minimum granularity value.
+ *
+ * To achieve this we use the following dynamic-granularity rule:
+ *
+ * gran = lat/nr - lat/nr/nr
+ *
+ * This comes out of the following equations:
+ *
+ * kA1 + gran = kB1
+ * kB2 + gran = kA2
+ * kA2 = kA1
+ * kB2 = kB1 - d + d/nr
+ * lat = d * nr
+ *
+ * Where 'k' is key, 'A' is task A (waiting), 'B' is task B (running),
+ * '1' is start of time, '2' is end of time, 'd' is delay between
+ * 1 and 2 (during which task B was running), 'nr' is number of tasks
+ * running, 'lat' is the the period of each task. ('lat' is the
+ * sched_latency that we aim for.)
+ */
+static long
+sched_granularity(struct cfs_rq *cfs_rq)
+{
+ unsigned int gran = sysctl_sched_latency;
+ unsigned int nr = cfs_rq->nr_running;
+
+ if (nr > 1) {
+ gran = gran/nr - gran/nr/nr;
+ gran = max(gran, sysctl_sched_min_granularity);
+ }
+
+ return gran;
+}
+