*
* Where A = pin 1, B = pin 2 and so on and pin=0 = default = A.
* Thus, each swizzle is ((pin-1) + (device#-4)) % 4
- *
- * The following code swizzles for exactly one bridge.
*/
-static inline int bridge_swizzle(int pin, unsigned int slot)
-{
- return (pin + slot) & 3;
-}
/*
* This routine handles multiple bridges.
if (pin == 0)
pin = 1;
- pin -= 1;
while (dev->bus->self) {
- pin = bridge_swizzle(pin, PCI_SLOT(dev->devfn));
+ pin = pci_swizzle_interrupt_pin(dev, pin);
/*
* move up the chain of bridges, swizzling as we go.
*/
dev = dev->bus->self;
}
- *pinp = pin + 1;
+ *pinp = pin;
return PCI_SLOT(dev->devfn);
}